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Explain why having 1/(new/old) has any bearing in this case.
Because I think you are playing with the numbers to try to prove your point.
Because I think you are playing with the numbers to try to prove your point.
Because it's the correct formula.
Ok, I'll explain this real slow for you.
Let's say we have 1000 delay with 40% haste
1000 x .6 = 600 delay
Let's say we have 1000 delay with 80% haste
1000 x .2 = 200
Now, we melee for 1800 units of delay
1800/600 = 3 attacks.
1800/200 = 9 attacks (in the same amount of time)
9/3 = 3( times as much) x 100 = 300% increase in number of attacks.
What formula matches this perfectly?
1/(200/600) = 3 (times as much) x 100 = 300%
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Sorry to say Tiger, but all haste stack affect delay reduction linearly and making haste effect exponential. Some sort of haste affect melee only, yes. like Samba March and Hasso.
You will always get the same delay reduction for every 1% haste you add,
Delay reduction = linear
Haste gain from it = exponential.
Tested numberous time.
You will always get the same delay reduction for every 1% haste you add,
Delay reduction = linear
Haste gain from it = exponential.
Tested numberous time.
You're wrong and you're right at the same time. Look at my last post, I said haste and DW are INDEPENDENT of each other. One has no effect on the other.
If you have 0% haste and 50% DW, you are going to get the same % increase in attack speed than if you have 0% DW and 50% haste. They are both exponential, but not to each other.
Haste is exponential to OTHER HASTE
DW is exponential to OTHER DW GEAR
Neither is exponential to the other.